Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 605: 25b

Answer

$T_H=341K$

Work Step by Step

We know that: $\epsilon=1-|\frac{Q_L}{Q_H}|$ As in the given scenario, efficiency is related to the temperature, hence $\epsilon=1-|\frac{T_L}{T_H}|$ This can be rearranged as: $T_H=\frac{T_H-T_L}{\epsilon}$ We plug in the known values to obtain: $T_H=\frac{75}{0.22}=341K$
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