Answer
$\frac{W}{p_1V_1} = -0.693$
Work Step by Step
Since step 1 is isothermal expansion, the first law of thermodynamics is
$Q = 0 + W$
$W = nRT_1 ln (\frac{V_2}{V_1})$
$W = nRT_1 ln (\frac{1}{2})$
$W = - p_1V_1 ln (2.00)$
$\frac{W}{p_1V_1} = -ln 2$
$\frac{W}{p_1V_1} = -0.693$
