Answer
$\Delta S = 1.94 \space J/K$
Work Step by Step
Change in entropy is given by
$\Delta S = nR ln (\frac{V_f}{V_i}) + n\frac{3}{2}R ln (\frac{T_f}{T_i})$
$\Delta S = nR [ln (2) + \frac{3}{2} ln (2e^{-1})]$
$\Delta S = \frac{p_iV_i }{T_i}[ln (2) + \frac{3}{2} ln (2) + \frac{3}{2} ln (e^{-1})]$
$\Delta S = \frac{p_iV_i }{T_i}[ \frac{5}{2} ln (2) - \frac{3}{2}]$
Plug in the values of $p_i, V_i \space and \space T_i$
$\Delta S = \frac{(5000Pa)(1.00m^3) }{600K}[ \frac{5}{2} ln (2) - \frac{3}{2}]$
$\Delta S = 1.94 \space J/K$
