Answer
$= 10.96 J/K$
Work Step by Step
The process of warming the water goes by
$\int ^{339.67} _{273.15} \frac{cm}{T} dT $
$ = cm [ln T]^{339.67} _{273.15}$
$ = cm [ln \frac{339.67}{237.15}]$
Where $ c =4190 J/Kg.^oC$
and $ m = 0.012 kg$
$ = (4190 J/Kg.^oC)(0.012 kg) [ln \frac{339.67}{273.15}]$
$= 10.96 J/K$
