Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 605: 19k

Answer

$\frac{\Delta E_{int}}{ p_1V_1 } = 4.5$

Work Step by Step

$\Delta E_{int} = Q_{total} - W_{total}$ $\Delta E_{int} = (\frac{15}{2}p_1V_1 - p_1V_1ln2.00) - (3p_1V_1 - p_1V_1 ln 2.00)$ $\Delta E_{int} = \frac{9}{2} p_1V_1 $ $\frac{\Delta E_{int}}{ p_1V_1 } = \frac{9}{2}$ $\frac{\Delta E_{int}}{ p_1V_1 } = 4.5$
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