Answer
$\Delta S=14.6\frac{J}{K}$
Work Step by Step
We know that:
$\Delta S=S_f-S_i=\frac{Q}{T}$
and $\frac{Q}{T}=\frac{L_Fm}{T}$
$\implies \Delta S= \frac{L_Fm}{T}$
We plug in the known values to obtain:
$\Delta S=\frac{333\times 10^3(0.012)}{273.15}=14.6\frac{J}{K}$
