Answer
$\frac{Q}{p_1V_1} = 7.50$
Work Step by Step
Step 2 : Constant pressure with volume from $V_1$ to $2.00V_1$
$Q = C_p\Delta T$
Where $C_p = \frac{5}{2} R$
$Q = \frac{5}{2} R\Delta T$
$Q = \frac{5}{2} R(T_2 - T_1)$
$Q = \frac{5}{2} R T_1 (\frac{T_2}{T_1} - 1)$
Note that $T_2/T_1 = 4$
$Q = \frac{5}{2} p_1V_1(4 - 1)$
$Q = \frac{15}{2} p_1V_1$
$\frac{Q}{p_1V_1} = \frac{15}{2}$
$\frac{Q}{p_1V_1} = 7.50$
