Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 16 - Acid-Base Equilibria - Exercises - Page 719: 16.75b

Answer

The Kb of $C_6H_5O^-$ is approximately 7.69 $\times 10^{-5}$.

Work Step by Step

$K_a \times K_b = K_w$ $1.3\times 10^{-10} \times K_b = 10^{-14}$ $K_b = \frac{10^{-14}}{1.3\times10^{-10}}$ $K_b \approx 7.6923 \times 10^{-5} $
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