Chemistry: The Central Science (13th Edition)

$C_3H_7NH_2 + H_2O -> {C_3H_7NH_3}^+ + OH^-$ $Kb = \frac{[{C_3H_7NH_3}^+][OH^-]}{[C_3H_7NH_2]}$
1. Write the reaction: $C_3H_7NH_2 + H_2O -> {C_3H_7NH_3}^+ + OH^-$ 2. Now, write the Kb formula: $Kb = \frac{[Conjugate.Acid]*[OH^-]}{[Base]}$ $Kb = \frac{[{C_3H_7NH_3}^+][OH^-]}{[C_3H_7NH_2]}$