Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 16 - Acid-Base Equilibria - Exercises - Page 719: 16.71


$[OH^-]=0.022 M$ $pH=12.34$

Work Step by Step

$[OH^-]=x$ $K_b=6.4\times10^{-4}=\frac{x\times x}{0.075-x}$ We can assume that $x\lt\lt0.075$ Therefore, $x=\sqrt {6.4\times 10^-4\times 0.075}$ $x=[OH^-]=0.022 M$ $pOH=1.66$ $pH=14-pOH=12.34$
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