Chemistry: The Central Science (13th Edition)

by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.

Published by Prentice Hall

ISBN 10: 0321910419

ISBN 13: 978-0-32191-041-7

Chapter 16 - Acid-Base Equilibria - Exercises - Page 719: 16.70c

Answer

${C_6H_5CO_2}^{-} + H_2O -> {C_6H_5COOH} + OH^-$ $Kb = \frac{[{C_6H_5COOH}][OH^-]}{[{C_6H_5CO_2}^{-}]}$

Work Step by Step

1. Write the reaction: ${C_6H_5CO_2}^{-} + H_2O -> {C_6H_5COOH} + OH^-$ 2. Now, write the Kb formula: $Kb = \frac{[Conjugate.Acid]*[OH^-]}{[Base]}$ $Kb = \frac{[{C_6H_5COOH}][OH^-]}{[{C_6H_5CO_2}^{-}]}$

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