Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 16 - Acid-Base Equilibria - Exercises - Page 719: 16.75a

Answer

Because you can easily find the Kb of a base, using the Ka of his conjugate acid, with this formula: $K_a * K_b = K_w = 10^{-14}$

Work Step by Step

If we took the Ka of phenol: $Ka = 1.3 \times 10^{-10}$ $Ka * Kb = 10^{-14}$ $1.3 \times 10^{-10} * Kb = 10^{-14}$ $Kb = \frac{10^{-14}}{1.3 \times 10^{-10}}$ $Kb = 7.7 \times 10^{-5}$ We will find that the Kb of the phenolate is $7.7 \times 10^{-5}$
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