Answer
See graph and explanations.
Work Step by Step
See graph, use $F$ for $Focus$, $V$ for $Vertex$, and $A$ for $Asymptote$, the second hyperbola shifted 3 units right and 1 unit up from the original, which has been reflected in the new coordinates of the foci and vertexes.
The new asymptotes will also shift while keeping slopes unchanged.
To find the new asymptote equations, use the old slopes and a new point $(3,1)$ which came from the shifts from $(0,0)$.
Assume one asymptote is $y=\frac{3}{4}x+b$, plug-in $(3,1)$ to get $\frac{9}{4}+b=1$ or $b=-\frac{5}{4}$.
For the other asymptote, $y=-\frac{3}{4}x+c$, plug-in $(3,1)$ to get $-\frac{9}{4}+c=1$ or $c=\frac{13}{4}$.
