Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 9 - Analytic Geometry - Section 9.2 The Parabola - 9.2 Assess Your Understanding - Page 668: 62

Answer

$y^2=-(x-1)$

Work Step by Step

1. Use the given graph, the parabola opens to the left with vertex $(1,0)$, thus we have $(y)^2=-4p(x-1)$ 2. Use the point $(0,1)$ on the curve, we have $(1)^2=-4p(0-1)$ , thus $p=\frac{1}{4}$ 3. The equation is $y^2=-(x-1)$
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