Answer
$x^2=4(y+1)$
Work Step by Step
1. Use the given graph, the parabola opens up with vertex $(0,-1)$, thus we have $(x)^2=4p(y+1)$
2. Use the point $(2,0)$ on the curve, we have $(2)^2=4p(0+1)$, thus $p=1$
3. The equation is $x^2=4(y+1)$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Section 9.2 The Parabola - 9.2 Assess Your Understanding - Page 668: 58
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