Answer
vertex $(0,1)$, focus $(2,1)$, directrix $x=-2$
See graph.
Work Step by Step
1. We can identify that $y^2=2y=8x-1\Longrightarrow (y-1)^2=8x$ is a parabola opens to the right,
2. Compare with the standard form to get:
$p=2$, vertex $(0,1)$, focus $(2,1)$, directrix $x=-2$
3. Use symmetry and a few test points such as at $x=0,1,2,3,4$ to get the graph.
