Answer
vertex $(0,0)$, focus $(-4,0)$, directrix $x=4$
See graph.
Work Step by Step
1. We can identify that $y^2=-16x$ is a parabola opens to the left,
2. Compare with the standard form to get:
vertex $(0,0)$, $p=4$, focus $(-4,0)$, directrix $x=4$
3. Use symmetry and a few test points such as at $x=0,-1,-2,-3,-4$ to get the graph.
