Answer
vertex $(2,3)$, focus $(2,4)$, directrix $y=2$
See graph.
Work Step by Step
1. We can identify that $(x-2)^2=4(y-3)$ is a parabola opens upward,
2. Compare with the standard form to get:
vertex $(2,3)$, $p=1$, focus $(2,4)$, directrix $y=2$
3. Use symmetry and a few test points such as at $x=2,3,4$ to get the graph.
