Answer
vertex $(2,-3)$, focus $(4,-3)$, directrix $x=0$
See graph.
Work Step by Step
1. We can identify that $(y+3)^2=8(x-2)$ is a parabola opens to the right,
2. Compare with the standard form to get:
vertex $(2,-3)$, $p=2$, focus $(4,-3)$, directrix $x=0$
3. Use symmetry and a few test points such as at $x=2,3,4$ to get the graph.
