Answer
vertex $(37,-6)$, focus $(\frac{147}{4},-6)$, directrix $x=\frac{149}{4}$
See graph.
Work Step by Step
1. We can identify that $y^2+12y=-x+1\Longrightarrow (y+6)^2=-(x-37)$ is a parabola opens to the left,
2. Compare with the standard form to get:
$p=\frac{1}{4}$, vertex $(37,-6)$, focus $(\frac{147}{4},-6)$, directrix $x=\frac{149}{4}$
3. Use symmetry and a few test points to get the graph.
