Answer
vertex $(0,0)$, focus $(0,1)$, directrix $y=-1$
See graph.
Work Step by Step
1. We can identify that $x^2=4y$ is a parabola opens upward,
2. Compare with the standard form to get:
vertex $(0,0)$, $p=1$, focus $(0,1)$, directrix $y=-1$
3. Use symmetry and a few test points such as at $x=0,1,2,3,4$ to get the graph.
