Answer
$y^2=\frac{1}{2}(x+2)$
Work Step by Step
1. Use the given graph, the parabola opens to the right with vertex $(-2,0)$, thus we have $(y)^2=4p(x+2)$
2. Use the point $(0,1)$ on the curve, we have $(1)^2=4p(0+2)$, thus $p=\frac{1}{8}$
3. The equation is $y^2=\frac{1}{2}(x+2)$
