Answer
vertex $(2,-8)$, focus $(2, -\frac{31}{4})$, directrix $y=-\frac{33}{4}$
See graph.
Work Step by Step
1. We can identify that $x^2-4x=y+4\Longrightarrow (x-2)^2=(y+8)$ is a parabola opens upward,
2. Compare with the standard form to get:
$p=\frac{1}{4}$, vertex $(2,-8)$, focus $(2, -\frac{31}{4})$, directrix $y=-\frac{33}{4}$
3. Use symmetry and a few test points such as at $x=0,1,2$ to get the graph.
