Answer
vertex $(3,-1)$, focus $(3,-\frac{5}{4})$, directrix $y=-\frac{3}{4}$
See graph.
Work Step by Step
1. We can identify that $(x-3)^2=-(y+1)$ is a parabola opens downward,
2. Compare with the standard form to get:
vertex $(3,-1)$, $p=\frac{1}{4}$, focus $(3,-\frac{5}{4})$, directrix $y=-\frac{3}{4}$
3. Use symmetry and a few test points such as at $x=3,4,5$ to get the graph.
