Answer
vertex $(2,-1)$, focus $(1,-1)$, directrix $x=3$
See graph.
Work Step by Step
1. We can identify that $(y+1)^2=-4(x-2)$ is a parabola opens to the left,
2. Compare with the standard form to get:
vertex $(2,-1)$, $p=1$, focus $(1,-1)$, directrix $x=3$
3. Use symmetry and a few test points such as at $x=0,1,2$ to get the graph.
