Answer
vertex $(-1,2)$, focus $(1,2)$, directrix $x=-3$
See graph.
Work Step by Step
1. We can identify that $(y-2)^2=8(x+1)$ is a parabola opens to the right,
2. Compare with the standard form to get:
vertex $(-1,2)$, $p=2$, focus $(1,2)$, directrix $x=-3$
3. Use symmetry and a few test points such as at $x=-1, 0,1,2,3$ to get the graph.
