Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 402: 46

Answer

$-2$

Work Step by Step

Note that $\sec x=\frac{1}{\cos x}$ and $\csc x=\frac{1}{\sin x}$ We use the unit circle values to simplify. Since $\cos{\pi}=-1$ and $\sin{\frac{\pi}{2}}=1$, then $\sec \pi - \csc \frac{\pi}{2}\\ = \dfrac{1}{ \cos (\pi)} - \dfrac{1}{ \sin (\pi/2)} \\ =\frac{1}{-1}-\frac{1}{1}\\ =-1 -1 \\= -2$
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