Answer
$\ P=\left(\frac{1}{2}, \frac{\sqrt{3}}{2}\right)$
Work Step by Step
$\theta=\frac{\pi}{3}$
The point on the Unit circle
$=(\cos \theta, \sin \theta)$
$=\left(\cos \frac{\pi}{3}, \sin \frac{\pi}{3}\right)$
$\therefore P=\left(\frac{1}{2}, \frac{\sqrt{3}}{2}\right)$