Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 402: 35

Answer

$\dfrac{1}{2}$

Work Step by Step

We need to compute $\sin 45^{\circ} \cos 45^{\circ}$. We use the unit circle values (where $\cos{45^{\circ}}=\frac{\sqrt2}{2}$ and $\sin{45^{\circ}}=\frac{\sqrt2}{2}$) to obtain: $\sin 45^{\circ} \cos 45^{\circ} \\ =(\dfrac{\sqrt 2}{2}) \times (\dfrac{\sqrt 2}{2}) \\ =\dfrac{2}{4}\\ =\dfrac{1}{2}$
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