## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$3+\sqrt 2$
We use the unit circle values to simplify. Since :$\sin{\frac{\pi}{4}}=\frac{\sqrt2}{2}$ and $\tan{\frac{\pi}{4}}=1$, then $2 \ \sin \frac{\pi}{4} + 3 \tan \frac{\pi}{4}\\ = (2) (\frac{\sqrt 2}{2}) + (3) (1) \\ =\sqrt 2 + 3\\ =3+\sqrt2$