Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 402: 42

Answer

$3+\sqrt 2$

Work Step by Step

We use the unit circle values to simplify. Since :$\sin{\frac{\pi}{4}}=\frac{\sqrt2}{2}$ and $\tan{\frac{\pi}{4}}=1$, then $2 \ \sin \frac{\pi}{4} + 3 \tan \frac{\pi}{4}\\ = (2) (\frac{\sqrt 2}{2}) + (3) (1) \\ =\sqrt 2 + 3\\ =3+\sqrt2$
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