Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 402: 26

Answer

$1$

Work Step by Step

We need to compute $\sec (8 \pi)$. The trigonometric function $\csc$ has a period of $2\pi$. Thus, we can simplify as follows: $\sec (8 \pi) =\sec (8 \pi+0 ) \\ =\sec (0) \\ =1$
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