Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 402: 27



Work Step by Step

We need to compute $\cos (\dfrac{-3 \pi}{2})$. The trigonometric function $\cos$ has a period of $2\pi$. Also, because cosine is even, $\cos (-x)=\cos (x)$ Thus, we can simplify as follows: $\cos (\dfrac{-3 \pi}{2}) =\cos (\dfrac{3 \pi}{2}) \\ =0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.