Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 402: 44

Answer

$1+2\sqrt 3$

Work Step by Step

Note that $\csc x=\dfrac{1}{\sin x}$ and $\cot x=\dfrac{1}{\tan x}$ We use the unit circle values to simplify. Since $\sin{\frac{\pi}{3}}=\frac{\sqrt3}{2}$ and $\tan{\frac{\pi}{4}}=1$, then $3 \ \csc \frac{\pi}{3} + \cot \frac{\pi}{4}\\ =3 \cdot \dfrac{1}{\sin{\frac{\pi}{3}}} + \dfrac{1}{\tan{\frac{\pi}{4}}}\\ = \dfrac{3}{\frac{\sqrt3}{2}} + \dfrac{1}{1} \\ =3\cdot \frac{2}{\sqrt3} + 1 \\ =\frac{6}{\sqrt3}+1\\ =\frac{6\sqrt3}{3}+1\\ =2\sqrt3+1\\ =1+2\sqrt3$
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