Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 402: 45

Answer

$1$

Work Step by Step

Note that $\csc x=\frac{1}{\sin x}$ and $\cot x=\frac{\cos{x}}{\sin{x}}$ We use the unit circle values to simplify. Since $\sin{\frac{\pi}{2}}=1, \cos{\frac{\pi}{2}}=0,$ and $\sin{\frac{\pi}{2}}=1$, then: $\csc \frac{\pi}{2} + \cot \frac{\pi}{2}\\ = \dfrac{1}{ \sin {\frac{\pi}{2}}} + \dfrac{\cos{\frac{\pi}{2}}}{ \sin{\frac{\pi}{2}}} \\ =\dfrac{1}{1}+\dfrac{0}{1}\\ =1+ 0 \\ =1$
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