Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 402: 31

Answer

$\dfrac{1+\sqrt 2}{2}$

Work Step by Step

We need to compute $\sin 45^{\circ}+\cos 60^{\circ}$. We use the know unit circle values to simplify as follows: $\sin 45^{\circ}+\cos 60^{\circ}=\dfrac{\sqrt 2}{2}+\dfrac{1}{2} \\=\dfrac{1+\sqrt 2}{2}$
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