Answer
$8$
Work Step by Step
We need to compute $5 \ \cos 90^{\circ} - 8 \sin 270^{\circ}$.
Since $\cos{90^\circ}=0$ and $\sin{270^\circ}=-1$, then:
$5 \ \cos 90^{\circ} - 8 \sin 270^{\circ} \\
= (5) (0)- (8) (-1) \\=0+8 \\=8$
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