Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 402: 40

Answer

$8$

Work Step by Step

We need to compute $5 \ \cos 90^{\circ} - 8 \sin 270^{\circ}$. Since $\cos{90^\circ}=0$ and $\sin{270^\circ}=-1$, then: $5 \ \cos 90^{\circ} - 8 \sin 270^{\circ} \\ = (5) (0)- (8) (-1) \\=0+8 \\=8$
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