Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.1 - The Ellipse - Exercise Set - Page 966: 48


See graph and explanations.

Work Step by Step

Step 1. Given $\frac{(x+1)^2}{2}+\frac{(y-3)^2}{5}=1$, we have $a^2=5, b^2=2$ and $c=\sqrt {a^2-b^2}=\sqrt 3$. The ellipse is centered at $(-1,3)$ with a vertical major axis. Step 2. We can graph the equation as shown in the figure with foci at $(-1,3\pm\sqrt 3)$.
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