Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.1 - The Ellipse - Exercise Set - Page 966: 8

Answer

See graph and explanations.

Work Step by Step

Step 1. Given $\frac{x^2}{64}+\frac{y^2}{100}=1$, we can identify $a^2=100, b^2=64$, thus $c=\sqrt {a^2-b^2}=6$. The ellipse is centered at $(0,0)$ with a vertical major axis. Step 2. We can graph the equation as shown in the figure, and the foci can be located at $(0, \pm6)$
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