Answer
See graph and explanations.
Work Step by Step
Step 1. Given $\frac{(x+3)^2}{9}+\frac{(y-2)^2}{1}=1$, we have $a^2=9, b^2=1$ and $c=\sqrt {a^2-b^2}=2\sqrt 2$. The ellipse is centered at $(-3,2)$ with a horizontal major axis.
Step 2. We can graph the equation as shown in the figure with foci at $(-3\pm2\sqrt 2,2)$.
See graph and explanations.
