Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.1 - The Ellipse - Exercise Set - Page 966: 26

Answer

$\frac{x^2}{36}+\frac{y^2}{32}=1$

Work Step by Step

Step 1. Based on the given conditions, we have $c=2, a=6$; thus $b^2=a^2-c^2=32$. The ellipse is centered at $(0,0)$ with a horizontal major axis. Step 2. We can write the equation as $\frac{x^2}{36}+\frac{y^2}{32}=1$
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