Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.1 - The Ellipse - Exercise Set - Page 966: 35



Work Step by Step

Step 1. Based on the given conditions, we have $a=\frac{9-3}{2}=3, b=\frac{9-5}{2}=2$ with a vertical major axis. The ellipse is centered at $(\frac{5+9}{2},\frac{9+3}{2})$ or $(7,6)$. Step 2. We can write the equation as $\frac{(x-7)^2}{4}+\frac{(y-6)^2}{9}=1$
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