Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.1 - The Ellipse - Exercise Set - Page 966: 23

Answer

$\frac{(x+1)^2}{4}+\frac{(y-1)^2}{1}=1$, foci $(-1\pm\sqrt 3,1)$

Work Step by Step

Step 1. From the given graph, we can identify $a=\frac{1-(-3)}{2}=2, b=1$; thus $c=\sqrt {a^2-b^2}=\sqrt {3}$. The ellipse is centered at $(-1,1)$ with a horizontal major axis. Step 2. We can write the equation as $\frac{(x+1)^2}{4}+\frac{(y-1)^2}{1}=1$ with foci at $(-1\pm\sqrt 3,1)$
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