Answer
See graph and explanations.
Work Step by Step
Step 1. Rewrite the equation as $4x^2+y^2=1$; we can identify $a^2=1, b^2=\frac{1}{4}$. Thus $c=\sqrt {a^2-b^2}=\frac{\sqrt 3}{2}$. The ellipse is centered at $(0,0)$ with a vertical major axis.
Step 2. We can graph the equation as shown in the figure, and the foci can be located at $(0,\pm\frac{\sqrt 3}{2})$
