Answer
$\frac{(x-2)^2}{25}+\frac{(y+3)^2}{100}=1$
Work Step by Step
Step 1. Based on the given conditions, we have $a=\frac{20}{2}=10, b=\frac{10}{2}=5$.
The ellipse is centered at $(2,-3)$ with a vertical major axis.
Step 2. We can write the equation as $\frac{(x-2)^2}{25}+\frac{(y+3)^2}{100}=1$
