## Precalculus (6th Edition) Blitzer

$\frac{(x+2)^2}{4}+\frac{(y-3)^2}{25}=1$
Step 1. Based on the given conditions, we have $a=\frac{10}{2}=5, b=\frac{4}{2}=2$. The ellipse is centered at $(-2,3)$ with a vertical major axis. Step 2. We can write the equation as $\frac{(x+2)^2}{4}+\frac{(y-3)^2}{25}=1$