Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.1 - The Ellipse - Exercise Set - Page 966: 41

Answer

See graph and explanations.
1585006040

Work Step by Step

Step 1. Given $\frac{(x-4)^2}{9}+\frac{(y+2)^2}{25}=1$, we have $a^2=25, b^2=9$ and $c=\sqrt {a^2-b^2}=4$. The ellipse is centered at $(4,-2)$ with a vertical major axis. Step 2. We can graph the equation as shown in the figure with foci at $(4,-6)$ and $(4,2)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.