# Chapter 9 - Section 9.1 - The Ellipse - Exercise Set - Page 966: 28

$\frac{x^2}{7}+\frac{y^2}{16}=1$

#### Work Step by Step

Step 1. Based on the given conditions, we have $c=3, a=4$; thus $b^2=a^2-c^2=7$. The ellipse is centered at $(0,0)$ with a vertical major axis. Step 2. We can write the equation as $\frac{x^2}{7}+\frac{y^2}{16}=1$

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