Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.1 - The Ellipse - Exercise Set - Page 966: 50

Answer

See graph and explanations.
1585008067

Work Step by Step

Step 1. Rewrite the given equation as $\frac{(x+4)^2}{1}+\frac{(y+3)^2}{36}=1$; we have $a^2=36, b^2=1$ and $c=\sqrt {a^2-b^2}=\sqrt {35}$. The ellipse is centered at $(-4,-3)$ with a vertical major axis. Step 2. We can graph the equation as shown in the figure with foci at $(-4,-3\pm\sqrt {35})$.
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