Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.1 - The Ellipse - Exercise Set - Page 966: 50


See graph and explanations.

Work Step by Step

Step 1. Rewrite the given equation as $\frac{(x+4)^2}{1}+\frac{(y+3)^2}{36}=1$; we have $a^2=36, b^2=1$ and $c=\sqrt {a^2-b^2}=\sqrt {35}$. The ellipse is centered at $(-4,-3)$ with a vertical major axis. Step 2. We can graph the equation as shown in the figure with foci at $(-4,-3\pm\sqrt {35})$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.