Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 73

Answer

See below.

Work Step by Step

$LHS=\frac{1}{cos\theta}-cos\theta=\frac{1-cos^2\theta}{cos\theta}=\frac{sin^2\theta}{cos\theta}=sin\theta tan\theta=RHS$
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