Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 476: 28

Answer

See explanations.

Work Step by Step

$LHS=sin(u)\cdot \frac{1}{sin(u)}-cos^2(u)=1-cos^2(u)=sin^2(u)=RHS$
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